Determine três soluções para cada uma das equações:
b) 3x-y=6
c) 5x+6y=60
Respostas
1
a)
2x + 3y = 12
3y = 12 – 2x
y = 12/3 – (2/3)x
x y = 4 – (2/3)x P(x, y)
2 = 4 -(2/3)(4)
= 4 – 8/3
= (12 – 8)/3
= 4/3 (2, 4/3)
0 y = 4 – (2/3)(0)
= 4 – 0
= 4 (0, 4)
– 1 y = 4 – (2/3)(-1)
= 4 + 2/3
= (12 + 2)/3
= 14/3 (-1, 14/3)
b)
Igual a)
3x – y = 6
3x – 6 = y
x y = 3x – 6 P(x, y)
3 = 3(3) – 6
= 9 – 6
= 3 (3, 3)
-3 y = 3(-3) – 6
= -9 – 6
= – 15 (-3, -15)
5 y = 3(5) – 6
= 15 – 6
= 9 (5, 9)
c)
5x + 6y = 60
6y = 60 – 5x
y = 60/6 – (5/6)x
y = 10 – (5/6)x
x y = 10 – (5/6)x P(x, y)
6 = 10 – (5/6)(6)
= 10 – 5
= 5 (6, 5)
– 6 y = 10 – (5/6)(-6)
= 10 + 5
= 15 (-6, 15)
12 y = 10 – (5/6)(12)
= 10 – (5.2)
= 10 – 10
= 0 (12, 0)
2
Ola Thayane
a) 2x + 3y = 12
S = ( (3,2), 6,0), (0,4) )
b) 3x – y = 6
S = ( (0,-6), (2,0), (3,3) )
c) 5x + 6y = 60
S = ( (0,10), (12,0), (18, -5) )